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lys-0071 [83]
3 years ago
15

Find the ratio of the following with solutiona. 30min:1.5hours​

Mathematics
2 answers:
mariarad [96]3 years ago
7 0
1.5 is the same as 90 minutes.

30 mins : 90 minutes

The highest common factor here is 30.

30 / 30 = 1

90 / 30 = 3

Therefore the solution to this is:

1:3

Hope this has helped you
scoray [572]3 years ago
4 0
Ok 30min:120 min

= divided both by 30

~ gives you 1:4
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Stella [2.4K]

42 times 28 = 1176

i'm 90% sure it's right please tell me if it's not

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3 years ago
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The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
What is the difference in length between the longest insect and the shortest insect centimeters
Dmitry [639]
Can't answer this question coz there is no numbers or pictures
5 0
4 years ago
Please answer the question bellow
valentina_108 [34]

No solution

because delta ( b^2 - 4ac ) is lower than 0(zero) .

6 0
3 years ago
The lengths of the sides of a triangle are 15 cm, 20 cm, 30 cm. What are the lengths of the sides of a similar triangle that has
Alexxandr [17]
<h3>Answer:</h3>

6 cm, 8 cm, 12 cm

<h3>Step-by-step explanation:</h3>

The perimeter of the reference triangle is  ...

... (15 +20 +30) cm = 65 cm

Then the similar triangle has a scale factor of ...

... (26 cm)/(65 cm) = 2/5

Multiplying the side lengths of the reference triangle by 2/5, we get ...

... {15 cm, 20 cm, 30 cm) × 2/5 = {6 cm, 8 cm, 12 cm}

These are the side lengths of the smaller similar triangle. (Check: their sum is 26 cm.)

4 0
3 years ago
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