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3 years ago

Just help ok? Image:

Mathematics

1 answer:

nekit [7.7K]3 years ago

3 0

Answer:

x=45

Step-by-step explanation:

The angles of a triangle always adds up to a total of 180 degrees. Since we are given two angles, we can solve this.

$75+60+x=180\\135+x=180\\x=45$

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Linear system word problem

soldi70 [24.7K]

Good job, you got the equations! XD

I'll just help you solve

Multiply the 2nd row by 9
9x+9y=117
9x+27y=207

Subtract the 2nd row from the 1st row
−18y=−90
Divide both sides by −18
y=−90/−18
Two negatives make a positive
y=90/18
y = 5

Substitute 5 into an equation
9x+9(5)=117
9x+45=117
Subtract 45 from both sides
9x=117−45

9x=72
Divide both sides by 9
x = ___

Hope this will help

3 0

3 years ago

How many minutes r there in 3 weeks

worty [1.4K]

30,240

60x24=1440x7=10,080x3= 30,240

3 0

3 years ago

Read 2 more answers

The relative growth rate for a certain type of mutual fund is 15% per year. An account is opened with a balance of $3,000. How m

wlad13 [49]

We have been given that an account is opened with a balance of $3,000 and relative growth rate for a certain type of mutual fund is 15% per year.

In order to tackle this problem we have to find the value of mutual fund after 5 years. For our purpose we will use compound interest formula.

$A=P(1+r)^{t}$ ,where A= amount after t years, P= principal amount, r= interest rate (decimal) and t= number of years.

After substituting our given values in above formula we will get

$A=3000(1+.15)^{5}$

Now we will solve for A

$A=3000(1+.15)^{5}=3000(1.15)^{5}\\ A=3000\cdot (2.011357187)=6034.07$

Therefore, after 5 years mutual fund is worth $6034.07.

8 0

4 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago

g The probability that a university graduate will be offered no jobs within a month of graduation is estimated to be 5%. The pro

dexar [7]

Answer:

49% probability that a graduate is offered fewer than two jobs

Step-by-step explanation:

We have these following probabilities:

5% probabilities of not being offered a job

44% probability of receiving one job offer

28% probability of received two job offers.

23% probability of receiving three job offers.

Determine the following probabilities: A. P(A graduate is offered fewer than two jobs)

Zero or one

5 + 44 = 49%

49% probability that a graduate is offered fewer than two jobs

8 0

3 years ago