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nikitadnepr [17]
3 years ago
11

A class of 33 students elected a class treasurer. There were 11 votes for Candidate A and 15 votes for Candidate B. The remainin

g students did not vote. Which expression gives the percent of voters who voted for Candidate A?

Mathematics
1 answer:
vovangra [49]3 years ago
5 0
To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.

Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:  
"number that chose candidate A" divided by "number of voters"

1) The numerator of the fraction should be the number of votes for candidate A, which is 11.

2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
</span>11 + 15 \: total \: votes

3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
\frac{11}{11+15}  \times 100

----

Answer: Top right choice, \frac{11}{11+15} \times 100
<span>

</span>
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Answer:

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x        1         2         3         4

y       5        8          11        14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

                                 = 3/1

                                  = 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

y\:=\:\frac{5}{3}x+3

comparing with the slope-intercept form of a linear function

y = mx+b     where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

y\:=\:\frac{5}{3}x+3

y\:=\:\frac{5}{3}\left(0\right)+3

y = 0+3

y = 3

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

8 0
3 years ago
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