Answer:
h = 19.6 ft
Step-by-step explanation:
Given that,
A 20 ft ladder 4ft from the base of the wall. 
The height of the ladder, H = 20 ft
The base distance, b = 4 ft
We need to find the height of the reach. Let it is P.
Using Pythagoras theorem,

or
P = 19.6 ft
So, the height is 19.6 ft.
 
        
             
        
        
        
Answer:
y = 2x^2 - 12x + 27
Step-by-step explanation:
<u>Step 1:  Distribute the power</u>
y = 2(x - 3)² + 9
y = 2(x^2 - 6x + 9) + 9
y = 2x^2 - 12x + 18 + 9
y = 2x^2 - 12x + 27
Answer:  y = 2x^2 - 12x + 27
 
        
             
        
        
        
Answer:
H=21ft
Step-by-step explanation:
Height=2•Area/Base
Area=126ft^2
Base=12ft.
H=2•126/12=21ft
H=21ft
Hope this helps :)
 
        
             
        
        
        
Answer:
36.50
To two decimal places
Step-by-step explanation:
The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.
From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.
Cos 51°=x/58
Let the size of the leg be x
Making x the subject
x=58(Cos51°)
x=36.500058
Correct to two decimal place
x=36.50