Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6). Qu
estion 3 options: a) y = –3x + 6 b) y = 13x − 2 c) y = 13x + 2 d) y = 3x – 6
2 answers:
Hello there,
Well first we need to write down what we know/what are we finding out...
- the original line has the equation of x - 3y = 5
- we are finding the equation of the line that is perpendicular
Now we start by changing the original equation to slope-intercept form:
- x - 3y = 5 as slope-intercept form would be y = 1/3x -5/3
Perpendicular lines have the negative reciprocal slopes so the new line has to have the slope as -3.
Option A would be the correct answer: a) y = -3x + 6
Hope I helped,
Amna
Answer:
a) y=-3x+6
Step-by-step explanation:
finding the slope of the given line:
-3y=-x+5
y=(1/3)x-(5/3)
since our new line has to be perpendicular to this line, our new line will have slope m=-3
putting these quantities into point-slope form:
y-6=-3(x-0)
converting to slope-int:
y=-3x+6
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