$3x + 4 > 16 \\ 3x > 16 - 4 \\ \frac{3x}{3} > \frac{12}{3} \\ x > 4 \\ \\ - 2x + 19 < 11 \\ - 2x < 11 - 19 \\ - 2x < - 8 \\ \frac{ - 2x}{ - 2} > \frac{ - 8}{ - 2} \\ x > 4 \\ \\ comparing \\ 4 < x > 4$

7 0

3 years ago

Simplify 2x + 1 - x +2.

Pavlova-9 [17]

Answer:

the answer is x + 3

Step-by-step explanation:

7 0

3 years ago

Solve this equation for x: 2x^2 + 12x - 7 = 0

zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: $2x^2 + 12x - 7 = 0$

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

$2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7$

Step 2: Divide the equation all through by the coefficient of $x^2$ which is 2.

$x^2 + 6x=\frac{7}{2}$

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3= $3^2$

Therefore, we have:

$x^2 + 6x+3^2=\frac{7}{2}+3^2$

Step 4: Write the Left Hand side in the form $(x+k)^2$

$(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\$

Step 5: Take the square root of both sides and solve for x

$x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355$

6 0

3 years ago