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kogti [31]
3 years ago
9

Can you help me please with number five

Mathematics
1 answer:
nirvana33 [79]3 years ago
3 0
0.5 gallons
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LenKa [72]
Factor the numerator and denominator and cancel the common factors.
4x^4 - 2
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2 years ago
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What would the answer be for this equation 7x/20 - 5x/12
hodyreva [135]

Answer:

\frac{1}{15} x

Step-by-step explanation:

\frac{7x}{20}  -  \frac{5x}{12}

\frac{3 \times 7x}{3 \times 20}  -  \frac{5 \times 5x}{5 \times 12}

\frac{21x}{60}  -  \frac{25x}{60}

\frac{21x - 25x}{60}  = (21 - 25)x =  - 4x

\frac{ - 4x}{60}  =  -  \frac{ x}{15}

\boxed{\green{=  \frac{1}{15} x}}

4 0
2 years ago
write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4
VashaNatasha [74]

Answer:

y= -3x + 8

Step-by-step explanation:

Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

and you have,

= y= -3x + 8

<em>(EDITED)</em> Steps:

2x+6y = -4

6y=2x - 4

y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

y = -3x + k ; k ∈ R

the line passes through the point (5,-7)

so,

-7 = -3. (5) +k

-7 = -15 + k

k = 8

∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

y= -3x + 8

Hope this helps, have a nice day/night! :D

6 0
2 years ago
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle
taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

Area  \  \   \alpha \ \  r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\  \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\  \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\


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3 years ago
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Six students, Michelle, Nadir, Olivia, Parvi, Quinn, and Richard, are running for four identical positions on student council. W
Scorpion4ik [409]
The answer to this question is 2/3
hope it helps
4 0
3 years ago
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