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4 years ago

Write 16t^1/5 in radical form

1 answer:

7 0

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 16t^{\frac{1}{5}}\implies 16\sqrt[5]{t^1}\implies 16\sqrt[5]{t}$

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20 POINTS!!!! HURRYYYYY

natulia [17]

Alternate exterior I believe

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3 years ago

Read 2 more answers

If S = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} and A =

ElenaW [278]

Answer:

a) = {0, 2, 3, 4, 5, 6, 8}, b = {0} empty set. c = {0, 1, 6, 7, 8, 9} d = {0, 1, 3, 5, 6, 7, 8, 9} e = {0, 1, 5, 6, 7, 8, 9} f = {2,4} .

Step-by-step explanation:

Given:

S = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

A = {0, 2, 4, 6, 8}

B = {1, 3, 5, 7, 9}

C = {2, 3, 4, 5}

D = {1, 6, 7}

Solution:

a) A∪C = A + C - A∩C

= {0, 2, 4, 6, 8} + {2, 3, 4, 5} - {2, 4}

= {0, 2, 2, 3, 4, 4, 5, 6, 8} - {2, 4}

= {0, 2, 3, 4, 5, 6, 8}

b) A∩B = ?

A∪B = A + B - A∩B

A∪B + A∩B = A + B

A∩B = A + B - A∪B

= {0, 2, 4, 6, 8} + {1, 3, 5, 7, 9} - {0, 1, 2, 3, 4, 5, 6, 8, 9}

= {0,1, 2, 3, 4, 5, 6,7, 8, 9} - {0, 1, 2, 3, 4, 5, 6, 8, 9}

A∩B = {0} empty set.

c) C′ = S - C

= {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 4, 5}

= {0, 1, 6, 7, 8, 9}

d) (C′∩D)∪B = ?

(C′∩D) = {0, 1, 6, 7, 8, 9} ∩ {1, 6, 7}

= {1, 6, 7}

B = {1, 3, 5, 7, 9}

(C′∩D)∪B = (C′∩D) + B - (C′∩D)∩B

= {0, 1, 6, 7, 8, 9} + {1, 3, 5, 7, 9} - {1, 7, 9,}

= {0, 1, 1, 3, 5, 6, 7, 7, 8, 9, 9} - {1, 7, 9,}

= {0, 1, 3, 5, 6, 7, 8, 9}

e) (S∩C)′ = S - (S∩C)′

(S∩C) = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} ∩ {2, 3, 4, 5}

= {2, 3, 4, 5}

(S∩C)′ = S - (S∩C)

= {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 3, 4, 5}

= {0, 1, 5, 6, 7, 8, 9}

f) A∩C∩D′ = ?

D′ = S - D

= {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} - {1, 6, 7}

= {0, 2, 3, 4, 5, 8, 9}

A∩C∩D′ = {0, 2, 4, 6, 8} ∩ {2, 3, 4, 5} ∩ {0, 2, 3, 4, 5, 8, 9}

= {2,4}

3 0

4 years ago

I need help with this

AlladinOne [14]

Answer:

A, B, and C

Step-by-step explanation:

We can substitute each number into each equation

2 < -1 + 5 true

2 > 1 true

1 > 0 true

A is correct

4 < -1 + 5 true

4 > 1 true

1 > 0 true

B is correct

3 < -0 + 5 true

3 > 0 true

0 > 0 true

C is correct

5 < -2 + 5 false

D is incorrect

3 0

3 years ago

Clare knows that Priya has a bunch of nickels and dimes in her pocket and that

enyata [817]

Answer:

a) 21 nickels and 2 dimes

b) $5x+10y=125$

c) There are 13 nickels and 6 dimes

d) The point (13,6) a solution to the equation you wrote

Step-by-step explanation:

Let x be the number of nickels and y be the number of dimes in Priya's pocket.

1 nickel = 5 cents

x nickels = 5x cents

1 dime = 10 cents

y dimes = 10y cents

b. Total amount in nickels and dimes is $5x+10y$ cents that is $1.25. Convert $1.25 into cents:

$\$1.25=125\ cents,$

so the equation that describes the relationship between the number of dimes and number of nickels is

$5x+10y=125$

a. To find one possible solution, substitute an arbitrary value of y and find x. Let y = 2, then

$5x+10\cdot 2=125\\ \\5x+20=125\\ \\5x=125-20\\ \\5x=105\\ \\x=21$

21 nickels and 2 dimes

c. The point (13,6) means that there are 13 nickels and 6 dimes.

d. Substitute x = 13 and y = 6 intoe the equation and check whether it is true:

$5\cdot 13+6\cdot 10=65+60=125$

True, so the point (13,6) a solution to the equation you wrote

5 0

3 years ago

if you wish to calculate the interst on an investment with a rate of 6.17%, what number will you plug into yourequation

Arisa [49]

Asked and answered elsewhere.
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3 0

4 years ago

Write 16t^1/5 in radical form​

Write 16t^1/5 in radical form