I am struggling on how to rationalize the denominators and simplify the problem.

im so confused and I'm ready to just throw my computer at the wall, how do you graph 3/5x + 9? i get the graphing the y intercep

Hunter-Best [27]

Answer:

start by placing a point on 9

Step-by-step explanation:

then use "rise over run" ( which is ri/ru) so you go up 3, then over 5. (hope this helps!)

8 0

2 years ago

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

2 years ago

How do you find the percent of a number greater than 100?

bonufazy [111]

Answer:

Multiply the number by the percent (e.g. 87 * 68 = 5916)

Divide the answer by 100 (Move decimal point two places to the left) (e.g. 5916/100 = 59.16)

Round to the desired precision (e.g. 59.16 rounded to the nearest whole number = 59)

Step-by-step explanation:

lets say for example 234

234/2 = 117 and the percentage were looking for is ummmm 25% well 25% is 1/4th of 234 making it 1/2 of 117 25% of 234 is 58.8 lets do a harder one what is 47% of 234 Divide n by 100.

Multiply the result by x. making it 109.98

4 0

2 years ago

Read 2 more answers

James is older than Benito. Benito is younger than Mariana. Mariana is younger than James. Describe how to

igomit [66]

Answer:bay summer homework???????

Step-by-step explanation:

bay?!?!?!!?

6 0

2 years ago

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