Answer:
See the answer below
Explanation:
Recall that: <em>Water potential = pressure potential + solute potential</em>
Since the system is an open one;
<em>Water potential = solute potential = -iCRT</em>
i = number of particles the molecle will make in water (1)
C = molar concentration
R = Pressure constant = 0.0831 liter bar/mole K
T = temperature in kelvin = 22 + 273 = 295 K
To calculate water potential on side A:
C = 1 M
Water potential = - (1 x 1 x 0.0831 x 295) = -24.51 bars
For side B:
C = 2 M
Water potential = - (1 x 2 x 0.0831 x 295) = -49.03 bars
b.
<em>Since side A has higher water potential than side B, water will flow from side A to side B until equilibrium is established between the two sides. Water always flows from the region of higher water potential to the region of lower water potential.</em>
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I was debating this question for the longest time and I came up with a conclusion.
No
Transpiration is the main driver
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