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zimovet [89]
3 years ago
13

You What is the range? 7 1 10 7 10 8 Submit

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer: 9

Step-by-step explanation: if the lowest number is 1 and the highest number is 10 then just find how far away these two numbers are in this case it is 9 numbers apart

hope this helps please mark me brainliest

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Find the nth term of the sequence:<br>23, 19, 13, 5, -5.......<br>​
Maurinko [17]

Answer:

Step-by-step explanation:

Given the sequence :

23, 19, 13, 5, -5.......

From the sequence, the common difference is unequal, as their is a constant Increment in the difference after successive numbers.

19 - 23 = -4

13 - 19 = -6

5 - 13 = -8

-5 - 5= -10

Hence an constant difference of - 2 after each successive difference.

Hence, this is a quadratic sequence

With the formula

an² + bn + c

8 0
3 years ago
Please help, ill give brainliest, only if its right
alexira [117]

Answer:

it would be in the fourth quadrant, directly underneath where it is now. the base would be c and d

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%7Bx%7D%5E%7B2%7Dy%20-%20%20%5Cfrac%7B8%7D%7B9%7Dx%20%7By%7D%5E%7B2
grin007 [14]

Answer:

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6 0
3 years ago
Help me<br><br>6 = 1/5 (4y + 10)​
gregori [183]

Step-by-step explanation:

open the bracket

6={(1/5×4y) + 1/5×10}

6=4/5y+2

6-2=4/5y

4=4/5y

divide both sides by 4/5

y=1/5

4 0
3 years ago
Read 2 more answers
Please help it’s urgent
katrin2010 [14]

\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

5 0
3 years ago
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