Does the choice of the base affect the area of the triangle

Find all polar coordinates of point P where P = (9,pi divided by 5).

RSB [31]

Answer:

(-9, π/5 + (2n + 1)π)

Step-by-step explanation:

Adding any integer multiple of 2π to the direction argument will result in full-circle rotations, which are identities, so this family is equivalent to the give coordinates:

(9, π/5 + 2nπ), for any integer n

Also, multiplying the radius by -1 is a point reflection, equivalent to a half-turn rotation. Then add π to the direction for another half turn, and the result is another identity. So this too is equivalent to the given coordinates:

(-9, π/5 + (2n + 1)π), for any integer n

7 0

3 years ago

Please help ASAP ASAP

Marrrta [24]

I can’t see it it’s blurry to me

4 0

2 years ago

Read 2 more answers

What is the coefficient of 43k?

OLEGan [10]

43.
The coefficient of something is the numerical value in that term. For example, if we have 4x. The coefficient is 4.

4 0

3 years ago

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Question 2 help me on the table

Alexxandr [17]

I THINK on b its that the percentages represent........................................................................................................................................READY.............UMMMMM............HOW MANY POEPLE GET A JOB ON HONEROLL OR TRY TO GET A JOB WHEN ITS HONNER ROLL OR NOTTTTTTTTTTTTTTTT.............................there u go........................byeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

3 0

3 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago