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anzhelika [568]
4 years ago
14

Elise wrote all possible four-digit numbers using two of the digit 2 and two of the digit 0. Two of Elise’s numbers have a great

er difference than any other pair. What is that difference?
Mathematics
1 answer:
Lyrx [107]4 years ago
6 0

Answer:

The required difference is 198.

Step-by-step explanation:

The four digit smallest number using 2,2,0,0 is =2002

The four digit largest number using 2,2,0,0 is =2200

Therefore the difference between 2200 and 2002 is =198

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2. Two angle measures are in the ratio 5:9. Write
iris [78.8K]

The two angles are x and 9x/5

<h3 /><h3 />

Let the two angles we require be x and y.

<h3 /><h3>Ratio of both angles</h3>

We have that the ratio of both angles are x:y

Since both angles are in the ratio 5:9, we have that,

x:y = 5:9

⇒ x/y = 5/9

<h3 /><h3>Value of the other angle</h3>

So, we Make y subject of the formula

Multiplying both sides by y, we have

y × x/y = 5/9 × y

x = 5y/9

Multiplying both sides by 9, we have

9 × x = 5y/9 × 9

9x = 5y

Dividing both sides by 5, we have

9x/5 = 5y/5

y = 9x/5

So, the two angles are x and 9x/5

Learn more about angles here:

brainly.com/question/14362353

3 0
3 years ago
Round 287.9412 to the nearest tenth. Do not write extra zeros.
goldenfox [79]
Salutations!

<span>Round 287.9412 to the nearest tenth. 

Lets solve this!

To round to the nearest tenth, you need to know the tenth place--------

In the number, 287.9412, nine is in the tenth place. You need also make sure whether the number next to 9 is greater than 5 or not. 

</span><span>287.9412 =287.941=287.94=287.9=288=290

Thus, your answer is 290.

Hope I helped.
</span>
3 0
3 years ago
Read 2 more answers
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
FOIL the following binomials. (6x+5)(1x+6)
andreyandreev [35.5K]
The trinomial that results from foiling the binomials is 6x^2+41x+30.
5 0
3 years ago
If a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hyp
maria [59]

Answer:

my hypothesis is that the answer is on page 31 of Harry potter and the Prisoner of Azkaban, it'll be the 48th word. God speed old chum

Step-by-step explanation:

3 0
3 years ago
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