Given:
Polynomial is 
.
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is
![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
On combining like terms, we get
Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 
.
The length of each side is 28 cm.
the perimeter of the equilateral triangle is 48 cm. To find each side of the original triangle, you do 48/3=16cm. since the triangle dilate by 0.75, then you can just do 0.75*16=12cm. then you have to add 12 to 16 because the triangle gets bigger by 12 cm. so 16+12=28 cm.
It might be 31 if you add all the numbers together but I'm not positive.
Answer:
No
Step-by-step explanation:
multiply each side of 6:1 by 3 to get it equivalent. 18:3 is not equal to 12:3 so no
Answer:
we must be doing the same problems
Step-by-step explanation:
I need help on them as well
