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sergeinik [125]
3 years ago
12

What is an apparent solution

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

an apparent solution that must be rejected because it does not satisfy the original equation.

Step-by-step explanation:

You might be interested in
Find the value of x<br> −8(x−6)=32
RUDIKE [14]

Answer:

x = 2

Step-by-step explanation:

-8(x-6) = 32 (distribute)

-8x+48 = 32 (subtract 48 from both sides)

-8x = -16 (divide)

x = 2

4 0
3 years ago
Read 2 more answers
How to solve <br> -3(4R-8)-36
natima [27]

Answer: -12r-12

Step-by-step explanation: There is no equals sign so you can't solve it but you can simplify it. You start out with -3(4r-8)-36. Then, you use PEMDAS. (-3×4r)+(-3×-8)-36. Then, it turns into -12r×+24-36. You just continue to simplify until you can't anymore. You end up with -12r-12.

7 0
4 years ago
What is the y-intercept of the line perpendicular to the line y = four thirdsx + 1 that includes the point (4, 1)?
s2008m [1.1K]

Answer:

(C)4

Step-by-step explanation:

Given the line: y=\dfrac43 x+1

The gradient of the line, m=\dfrac43

A line perpendicular to the given line will have a gradient, m=-\dfrac34 (by definition of perpendicularity).

Therefore, a perpendicular line that passes through the point (4,1) is:

y-y_1=m(x-x_1)\\y-1=-\dfrac34(x-4)\\y-1=-\dfrac34x+3\\y=-\dfrac34x+3+1\\y=-\dfrac34x+4

Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.

4 0
3 years ago
Events A and B are independent. find the missing probability<br> P(A)= 1/4 , P(B)= 3/5, P(B I A) =?
Svetach [21]

Answer:

hello : P(A and B) = 3/20

Step-by-step explanation:

events A and B are independent:

P(A and B) = P(A)×P(B)

P(A and B) = (1/4)×(3/5)

P(A and B) =3/20

continu ....

P(B/A)= P(A and B) / P(A)

3 0
4 years ago
Existen tres órdenes de producción en proceso. Las ordenes A y B juntas tienen 150 unidades; B y C juntas, 100 unidades, y A y
Oksanka [162]
Orders are a, b, c, lets write equations to represent the problem's info:
a + b = 150
b + c = 100
a + c = 150
so we have 3 unknowns and 3 equations, so we can solve.
<span>Use the first equation:
a + b = 150
</span>a = 150 - b
and substitute in the 3rd:
<span>a + c = 150
</span>150 - b + c = 150
then
b = c
and we can substitute that in the original equation:
<span>b + c = 100
</span>2b = 100
b = 50
c = 50
and substitute in the first equation:
<span>a + b = 150
</span>a = 150 - b = 150 - 50
a = 100
then a = 100, b = c = 50
3 0
3 years ago
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