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Westkost [7]
3 years ago
8

How to solve this and find x and y variables.

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0
Y equals 64 and x equals 30
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ILL MARK BRAINLIEST AND GIVE FREE POINTS<br><br><br> Solve the system y = -x + 7 and y = 0.5(x - 3)2
Varvara68 [4.7K]

Answer:

Point Form:

( 5 , 2)

Equation Form:

x = 5 , y = 2

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

8 0
2 years ago
84÷0.02 samarian Roberts is very awsome and cool
insens350 [35]

0.02 can go into 84, 4200 times. Your answer is <u>incorrect</u>, the <u>correct answer</u> is 4200.

3 0
3 years ago
Read 2 more answers
If the perimeter of a square is 20, find the length of a diagonal
avanturin [10]

Answer:

7.07

Step-by-step explanation:

<h2><u>Length</u></h2>

a square has equal length on each side

hence is the perimeter is 20 it means that :

each side is 20/4 = 5

we can make a diagonal line which create 3 right angled triangles

2 sides of the triangle are 5 , this is the base and the height

to find the length we can make use of the Pythagoras theorem

c^2 = a^2 + b^2

c is the hypotenuse ( the diagonal;)

a and b are the opposite and adjacent

hence :

c^2 = 5 ^2 + 5^2

c^2 = 50

c = \sqrt{50}

c = 7.071

to 3sf

<h3><u>diagonal length  = 7.07</u></h3>

6 0
3 years ago
Calcule (1/2)-² POR FAVOR RESPONDEM​
dolphi86 [110]

Answer:

I think it's 1/4 or .25

4 0
2 years ago
Which triangle drfined by the given points on the coordinate plane is similar to the triangle illustrated? ​
Harrizon [31]

Answer:D.) (-1, 1), (-1, 5), (-7, 1)

Step-by-step explanation:The length of the horizontal segment of the triangle graphed is 3.  The length of the vertical segment of the triangle graphed is 2.  Using the Pythagorean theorem, this makes the length of the missing side

2²+3²=c²

4+9 = c²

13=c²

√13 = c

This makes our side lengths 2, 3, and √13.

For choice A our vertices are (-1, 1), (-1, 4), (-6, 1).

This makes the length of the horizontal segment 5 and the length of the vertical segment 3.  This makes the missing side length

5²+3²=c²

25+9=c²

34=c²

√34 = c

This is not proportional to the triangle drawn, so it is not similar.

The vertices of the triangle in option B are (-1, 1), (-1, 5), and (-6, 1).  This makes the horizontal segment 5 units long and the vertical segment 4 units long.  This makes the missing side length

4²+5²=c²

16+25=c²

41=c²

√41=c

These are not proportional to the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice C are (-1, 1), (-1, 4) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 3.  This makes the missing side length

3²+6²=c²

9+36=c²

45=c²

√45=c

3√5=c

These sides are not proportional to the sides of the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice D are (-1, 1), (-1, 5) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 4.  This makes the missing side length

6²+4²=c²

36+16=c²

52=c²

√52=c²

2√13=c

These sides are all twice as long as the sides of the triangle drawn; this means the triangles are similar.

4 0
3 years ago
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