Assuming the rotation is around the origin (0,0) then A' = A. The parallelogram is in its original location
What is the given matrix?
you didn't show a matrix.
the components of the matrix are the elements.
and the elements of the inverse matrix are the elements of the inverse matrix
1)
so if matrix A is 1 4 1
2 5 2
3 6 3
2)
14114
25225
36336
3)
15 24 12
15 12 24
4)
[A]=(15+24+12=51)-(15+12+24=51)
[A]=0
5)
52 23 25
63 23 36
41 11 14
63 33 36
41 12 14
52 12 25
6)
15-12 6-6 12-15
12-6 3-3 6-12
8-5 2-2 5-8
7)
3 0 -3
6 0 -6
3 0 -3
8)
(+)3 (-)0 (+)-3
(-)6 (+)0 (-)-6
(+)3 (-)0 (+)-3
=
3 0 -3
-6 0 6
3 0 -3
9)
3 -6 3
N= 0 0 0
-3 6 -3
10) the inverse of [A]= 1/|A|*[N]
which is in this case ⁻A= 0
because |A|=0
<u>Answer and explanation</u>
(1+sinθ)(1-sinθ)=cos²θ
We are to prove that the left hand side is equal to the right hand side.
(1+sinθ)(1-sinθ) = 1(1-sinθ) + sinθ(1-sinθ)
= 1 - sinθ + sinθ - sin²θ
= 1 - sin²θ
From the trigonometric identity sin²θ + cos²θ = 1,
1 - sin²θ = cos²θ
Answer:
-(x + 1)(7x - 12)
Step-by-step explanation:
Step 1: Factor out a -1
-1(7x² - 5x - 12)
Step 2:
Think. Answer this question: "What 2 numbers multiply up to -12 and adds up to -5 while 7 is an x coefficient?". You answer should be -12 and 1.
So, <em>factor</em>.
-1(x + 1)(7x - 12)
To double check, just expand/FOIL everything and see if it is the same as the original expression.
