Answer:
the sample should be 237
Step-by-step explanation:
The computation of the large the sample be used is shown below:
Given that
Standard deviation = 0.09 ounces
margin of error = 0.011
For 94% confidence interval, the z value be 1.88
As we know that
Margin of error = ((z score × standard deviation) ÷ (Sample size))^2
0.011 = (1.88 × 0.09) ÷ (Sample size))^2
0.011 = 0.1692 ÷ (Sample size))^2
So, the sample size be
= 15.38^2
= 236.60
Hence, the sample should be 237
