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Serga [27]
3 years ago
7

A statistical quality control process for cereal production measures the weight of a cereal box. The population standard deviati

on is known to be 0.09 ounces. If we wish to estimate the population average cereal box weight to within 0.011 ounces and be 94% confident, how large a sample should be used
Mathematics
1 answer:
algol133 years ago
5 0

Answer:

the sample should be 237

Step-by-step explanation:

The computation of the large the sample be used is shown below:

Given that

Standard deviation = 0.09 ounces

margin of error = 0.011

For 94% confidence interval, the z value be 1.88

As we know that

Margin of error = ((z score × standard deviation) ÷ (Sample size))^2

0.011 = (1.88 × 0.09) ÷ (Sample size))^2

0.011 = 0.1692 ÷ (Sample size))^2

So, the sample size be

= 15.38^2

= 236.60

Hence, the sample should be 237

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