All categories

3 years ago

I need help with Probability of compound events. I need steps of how doing it

1 answer:

const2013 [10]3 years ago

6 0

To find the probability of two independent events, multiply the probability of the first event by the probability of the second event

You might be interested in

Can some one help me with this??? Really need help

Vitek1552 [10]

$1-\frac{1}{3}-\frac{3}{7}=\\
\frac{21}{21}-\frac{7}{21}-\frac{9}{21}=\\
\frac{5}{21}$

6 0

3 years ago

Read 2 more answers

What is the exact value of BC? A. 3.16 B. 5\|2 C. 7.07 D. 25

Natalija [7]

Answer:

$C. \: \: 7.07$

Step-by-step explanation:

Coordinates of B are

$(5,5)$

Coordinates of C are

$(4, - 2)$

Distance between two points

$\sqrt{({x_2 - x _1 {)}^{2} + (y_2 - y_1 {)}^{2} }}$

Distance of BC

$\sqrt{(4 - 5) {}^{2} + ( - 2 - 5 {)}^{2} }$

$\sqrt{ { (- 1}^{2}) + ({ - 7}^{2}) }$

$\sqrt{1 +49 }$

$\sqrt{50}$

$7.07$

3 0

2 years ago

Solve for x. 4(2x + 1) = 3(x + 8)

il63 [147K]

4(2x+1) = 3(x+8)
8x + 4 = 3x + 24
5x = 20
∴x = 4

8 0

3 years ago

How much is 1/11 of 55

shepuryov [24]

Answer:5

Step-by-step explanation:

you just divide 55 by 11

8 0

3 years ago

Read 2 more answers

Please no links or files I need a direct answer.

Hatshy [7]

Answer:

$\text{a. }128\:\mathrm{cm^3},\\\text{b. }4:1,\\\text{c. }179.4\:\mathrm{cm^2};\:44.8\:\mathrm{cm^2}$

Step-by-step explanation:

The volume of a square pyramid is given by $V=\frac{1}{3}\cdot s^2\cdot h$

Since pyramids A and B are similar, their corresponding side lengths are proportion. Since the base edge of B is half that of A's, each dimension of B will be half of A. Since the formula for volume requires the multiplication of three dimensions, the volume of pyramid A will be $2^3=8$ times larger than the volume of pyramid B.

Thus, the volume of pyramid A is equal to $16\cdot 8=\boxed{128\:\mathrm{in^3}}$ . You can also find the dimensions of pyramid A and use the formula.

The surface area consists of the sum of all areas of the 2D shapes that make the figure. Since all dimensions of pyramid A are twice the dimensions of pyramid B, the ratio of the surface area of pyramid A to pyramid B is $2^2:1=\boxed{4:1}$

The surface area of a square pyramid can be found by adding the areas of the three triangles and one square that make it up. As one long messy formula, that becomes $2s\sqrt{\left(\frac{s}{2}\right)^2+h^2}+s^2$ for a square pyramid with base edge $s$ and height $h$ .

Plugging in values, we get the following:

$A_a\approx \boxed{179.4\:\mathrm{cm^2}},\\A_b\approx \boxed{44.8\:\mathrm{cm^2}}$

5 0

3 years ago