An imaginary number " i " is the squared root of -1, so whenever you square i it's like squaring a squared root. The squared root would cancel and you would be left with just the number under it, that is, the -1. 
i ^ 2 = -1
        
             
        
        
        
Answer: 
1. C. cylindrical coordinates 
2 A. spherical coordinates 
3. A. spherical coordinates
4. D. Cartesian coordinates
5  B. polar coordinates 
Step-by-step explanation:
USE THE BOUNDARY INTERVALS TO IDENTIFY
1. ∭E dV where E is:  
x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0  -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0 
2. ∭E z^2 dV where E is:  
-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES
3. ∭E z dV where E is:
1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES
4. ∫10∫y^20 1/x dx  ---- This is A CARTESIAN COORDINATES
5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4  This is A POLAR COORDINATES
 
        
             
        
        
        
Answer:
ok
Step-by-step explanation:
 
        
             
        
        
        
Answer:
See explanation
Step-by-step explanation:
3(x + 4) + 2 = 2 + 5(x – 4)
Step 1: distributive property
3(x + 4) + 2 = 2 + 5(x – 4)
3x + 12 + 2 = 2 + 5x - 20
Step 2: collect like terms
3x + 12 + 2 = 2 + 5x - 20
3x + 14 = 5x - 18
Step 3: Addition property of equality
3x + 14 = 5x - 18
3x + 14 + 18 = 5x - 18 + 18 
3x + 32 = 5x
Step 4: subtraction property of equality
3x + 32 - 3x = 5x - 3x
32 = 2x
Step 5: division property of equality
32 = 2x
32/2 = 2x/2
16 = x
x = 16
 
        
             
        
        
        
5x’2-4x+7-4x-2
We add the two 4 
5x’2-8x+7-2
5x’2-8x+5
The answer is 
5x’2 -8x +5