An imaginary number " i " is the squared root of -1, so whenever you square i it's like squaring a squared root. The squared root would cancel and you would be left with just the number under it, that is, the -1.
i ^ 2 = -1
Answer:
1. C. cylindrical coordinates
2 A. spherical coordinates
3. A. spherical coordinates
4. D. Cartesian coordinates
5 B. polar coordinates
Step-by-step explanation:
USE THE BOUNDARY INTERVALS TO IDENTIFY
1. ∭E dV where E is:
x^2 + y^2 + z^2<= 4, x>= 0, y>= 0, z>= 0 -- This is A CYLINDRICAL COORDINATES SINCE x>= 0, y>= 0, z>= 0
2. ∭E z^2 dV where E is:
-2 <= z <= 2,1 <= x^ 2 + y^2 <= 2 This is A SPHERICAL COORDINATES
3. ∭E z dV where E is:
1 <= x <= 2, 3<= y <= 4,5 <= z <= 6 -- This is A SPHERICAL COORDINATES
4. ∫10∫y^20 1/x dx ---- This is A CARTESIAN COORDINATES
5. ∬D 1/x^2 + y^2 dA where D is: x^2 + y^2 <=4 This is A POLAR COORDINATES
Answer:
ok
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
3(x + 4) + 2 = 2 + 5(x – 4)
Step 1: distributive property
3(x + 4) + 2 = 2 + 5(x – 4)
3x + 12 + 2 = 2 + 5x - 20
Step 2: collect like terms
3x + 12 + 2 = 2 + 5x - 20
3x + 14 = 5x - 18
Step 3: Addition property of equality
3x + 14 = 5x - 18
3x + 14 + 18 = 5x - 18 + 18
3x + 32 = 5x
Step 4: subtraction property of equality
3x + 32 - 3x = 5x - 3x
32 = 2x
Step 5: division property of equality
32 = 2x
32/2 = 2x/2
16 = x
x = 16
5x’2-4x+7-4x-2
We add the two 4
5x’2-8x+7-2
5x’2-8x+5
The answer is
5x’2 -8x +5
