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Liono4ka [1.6K]
3 years ago
15

shayla is financing a house for $126,750. She has to pay $450 plus 1.15% for a brokerage fee. How much are the mortgage brokerag

e fees?
Mathematics
1 answer:
ANEK [815]3 years ago
7 0
Answer: $1,907.63

Explanation:

It is stated in the problem that the brokerage fee is $450 plus 1.15% (meaning 1.15% of $126,750). Hence the brokerage fee is computed as follows
  
(Brokerage fee) = $450 + (1.15% of $126,750)
                          = $450 + (0.0115)($126,750) 
                          = $450 + $1,457.625
                          = $1,907.625

Since there is no half cents today, we round-off the brokerage fee to the nearest cent. Hence the brokerage fee is $1,907.63.

Note: In the computation of brokerage fee, we need to change 1.15% to  decimal.   
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Answer:Yes indeed

Step-by-step explanation:

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oceanside bike rental shop charges a $17 fixed fee plus six dollars an hour for renting a bike. Tim paid $47 to rent a bike. How
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Help find slope of each line
gizmo_the_mogwai [7]
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3 0
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Read 2 more answers
How do I solve for the fourth term in this sequence?
tatiyna

Answer:

<h2>d(4) = 64</h2>

Step-by-step explanation:

d(1) = 13

d(n) = d(n - 1) + 17

where

n is the nth term

To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term

So we have

<u>For the 2nd term</u>

That's d(2)

We have

d(2) = d(2-1) + 17

d(2) = d(1) + 17

But d(1) = 13

d(2) = 13 + 17 = 30

<u>For the 3rd term d(3)</u>

That's

d(3) = d(3 - 1) + 17

d(3) = d(2) + 17

d(3) = 30 + 17 = 47

<u>For the 4th term that's d(4)</u>

We have

d(4) = d(4 - 1) + 17

d(4) = d(3) + 17

d(4) = 47 + 17

We have the final answer as

<h3>d(4) = 64</h3>

Hope this helps you

3 0
3 years ago
in the ambrose family the ages of the three children are three consecutive even integers . if the age of the youngest child is r
klemol [59]

The ages are consecutive even numbers.
The youngest child is  (x+3) years old.
Every even number is 2 more than the one before it.
So the three ages are

           (x + 3),  (x + 5),  and  (x + 7).

Their sum is    x+3  +  x+5  +  x+7  =  3x + 15

But we're told that their sum is  42, so we can write

                                              3x + 15 = 42  <== the equation

Subtract 15 from each side:  3x         =  27

Divide each side by  3 :          x         =   9    <== the solution

So the three ages are  12,  14,  and  16.

The oldest child is  16  years old.

3 0
3 years ago
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