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AURORKA [14]
4 years ago
15

If Planes Q and R are parallel planes. Plane Q contains line a. Plane R contains line b. a third plane could be drawn which cont

ains both lines a and b, then
Mathematics
2 answers:
Anettt [7]4 years ago
8 0
If a third plane could be drawn which contains both lines a and b, then lines a and b must be parallel. <span>if two lines do not intersect on the same plane, they are parallel. Furthermore, if a line is in a plane and another line is in a parallel plane, you cannot draw another plane </span><span>which contains both lines a and b, only if the lines are parallel.</span>
storchak [24]4 years ago
6 0
Since parallel lines need to be in the same plane, if there were a plane (the third one) that had both lines, this would meet the requirements for parallel lines. So its parallel.
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Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
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stealth61 [152]

Answer:

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8 0
3 years ago
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Write the slope intercept form of the r question of the line parallel to the graph of 2x+y=5 that passes through (0,1)
Fofino [41]

Step-by-step explanation:

first let's get the original line in slope intercept form.

the vegetal slope intercept form is

y = ax + b

a is the slope, b is the y-intercept.

2x + y = 5

y = -2x + 5

there !

a line parallel to this line must have the same slope (-2).

but it will intersect with the y-axis at a different point.

the y-intersect is the y value when x = 0.

the given point (0, 1) is already that y-intersect (because x=0).

so, the desired parallel line function is

y = -2x + 1

if we had a different point of the line, e.g. (4, -7), we would go back to the general equation

y = ax + b

put in the slope we know (-2)

y = -2x + b

and then put in the x and y cakes if the point and calculate b

-7 = -2×4 + b

-7 = -8 + b

b = 1

and then we get again

y = -2x + 1

4 0
2 years ago
What is 11 feet and 8 inches plus 2 feet and 9 inches
Agata [3.3K]

Answer:

14 feet and 5 inches

Step-by-step explanation:

11 feet + 2 feet= 13 feet

9 inches + 8 inches = 17 inches

17 inches = 1 foot and 5 inches

13 + 1 = 14 feet

5 inches + 0 inches = 5 inches

7 0
3 years ago
Write the following as an algebraic expression:<br><br> Twice the cube of z
konstantin123 [22]

Answer:

z^3 • z^3 ? or z^3^2 ?

Step-by-step explanation:

7 0
3 years ago
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