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AURORKA [14]
3 years ago
15

If Planes Q and R are parallel planes. Plane Q contains line a. Plane R contains line b. a third plane could be drawn which cont

ains both lines a and b, then
Mathematics
2 answers:
Anettt [7]3 years ago
8 0
If a third plane could be drawn which contains both lines a and b, then lines a and b must be parallel. <span>if two lines do not intersect on the same plane, they are parallel. Furthermore, if a line is in a plane and another line is in a parallel plane, you cannot draw another plane </span><span>which contains both lines a and b, only if the lines are parallel.</span>
storchak [24]3 years ago
6 0
Since parallel lines need to be in the same plane, if there were a plane (the third one) that had both lines, this would meet the requirements for parallel lines. So its parallel.
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Answer:

16,771.56 square feet.

Step-by-step explanation:

In order to get to the result we will need to use the scale and the numbers that are provided of the dimensions of the room.

The dimensions of the room on the floor plan are 17.8 inches by 21.2 inches. We first need to multiply these numbers with the scale:

17.8 x 80 = 1,424

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Now that we got the real measures we need to multiply these two values in order to get to a result as in how many square inches is the room:

1,424 x 1696 = 2,425,104

Now we need to convert the square inches into square feet to get to the final result:

1 ft² = 144 in²

2,425,104 / 144 = 16,771.56

So we have a result of 16,771.56 square feet.

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3 years ago
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Sauron [17]
Your answer would be B.

The triangles would be congruent, because the lines GH and FI are congruent and the angle H and I are the same, and since the line HI is shared by the two, it would then be SAS.
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