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SOVA2 [1]
3 years ago
11

At the city museum child admission is $5.70 and the adult admission is $9.60 on Thursday,186 ticket were sold for a total sales

of $1399.50. How many child tickets were sold that day?

Mathematics
1 answer:
QveST [7]3 years ago
8 0
I hope this helps you

You might be interested in
Write the integer from least to greatest. 4, 12, -12, -11
maxonik [38]

Answer:

-12, -11, 4, 12

Step-by-step explanation:

A negative number is less the higher it is, and a positive number is more the higher it is

3 0
2 years ago
What is 1323/12 in simplified form
Mice21 [21]

Answer:

441/4

Step-by-step explanation:

Find the GCD of numerator and denominator

GCD of 1323 and 12 is 3

Divide both the numerator and denominator by the GCD

1323 ÷ 3

12 ÷ 3

Reduced fraction:

441/4

________

Hope this helps!

-Lexi

4 0
2 years ago
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
3 years ago
100 POINT QUESTION
Valentin [98]

its not 100 points it 8 but i will still help you

the answer is 7.2 i believe

4 0
3 years ago
What are the next 2 numbers in the pattern 1, 4, 9, 16, 25, 36, 49, . . .
GREYUIT [131]
This pattern is adding the next odd number, starting with 3. For example, we can use the first few numbers:
1 + 3 = 4
4 + 5 = 9
9 + 7 = 16

This means that when we reach 49, we have to add 17 into it to get the answer of 66.
4 0
3 years ago
Read 2 more answers
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