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3 years ago

Which of the statements below is true for the following set of numbers? 30,25,50,75,75,60

1 answer:

6 0

<h2><em>The range and mid-range are equal</em></h2><h2><em>the range is 75-25=50 </em></h2><h2><em> the mid-range is (75+25)/2 = 100/2 = 50 </em></h2><h2><em> 50 = 50</em></h2><h2><em> HOPE IT HELPS (◕‿◕✿) </em></h2><h2><em> SMILE!!</em></h2>

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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

<em>Choose the first alternative</em>

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

3 years ago

Read 2 more answers

The Petersons deposited $1,000 in an account that earns 2% annual simple interest. How many years will it take the amount in the

noname [10]

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8 0

3 years ago

What is the x-value of the solution of the system of

Nady [450]

Answer:

x = -1, y = -4

Step-by-step explanation:

Let's solve our system of equations by substitution.

y = 5x + 9y = −x + 3

Step: Solve = 5x + 9 for y:

y = 5x + 9

Step: Substitute 5x + 9 for y in y = −x + 3:

y = −x + 3

5x + 9 = −x + 3

5x + 9 + x = −x + 3 + x (Add x to both sides)

6x + 9 = 3

6x + 9 + −9 = 3 + −9 (Add -9 to both sides)

6x = −6

6x/ 6 = −6/6(Divide both sides by 6)

x = −1

Step: Substitute −1 for x in y = 5x + 9:

y = 5x + 9

y = (5)(−1) + 9

y = 4(Simplify both sides of the equation)

So our answers are y = -4 and x = -1.

8 0

4 years ago

What two numbers have a GCF of 5 and a LCM of 50

Komok [63]

Answer:

10 and 5

Step-by-step explanation:

5 0

3 years ago

What is H in the algebraic expression H+340÷30=25

disa [49]

Answer:

H = 13.67

Step-by-step explanation:

Given:

The the algebraic expression is

$H + \frac{340}{30} = 25$

We need to write the above equation for h.

Solution:

$H + \frac{340}{30} = 25$

First we divide the fraction part of the equation by common factor 10.

$H + \frac{34}{3} = 25$

Subtract both side of the equation by $\frac{34}{3}$ .

$H + \frac{34}{3}-\frac{34}{3} = 25- \frac{34}{3}$

$H = 25- \frac{34}{3}$

To write 25 as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$H = 25\times \frac{3}{3}- \frac{34}{3}$

$H = \frac{25\times3}{3}- \frac{34}{3}$

$H = \frac{75}{3}- \frac{34}{3}$

$H = \frac{75-34}{3}$

$H = \frac{41}{3}$

$H = 13.67$

Therefore the value of H is 13.67.

7 0

3 years ago