Which of the statements below is true for the following set of numbers? 30,25,50,75,75,60

1 answer:

6 0

<h2><em>The range and mid-range are equal</em></h2><h2><em>the range is 75-25=50 </em></h2><h2><em> the mid-range is (75+25)/2 = 100/2 = 50 </em></h2><h2><em> 50 = 50</em></h2><h2><em> HOPE IT HELPS (◕‿◕✿) </em></h2><h2><em> SMILE!!</em></h2>

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Which of the following is the same as 8.4x10²

Marta_Voda [28]

Answer:

840

Step-by-step explanation:

8.4x10^2

8.4x100

move the decimal to the right for the amount of zeros :)

840

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3 years ago

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What is the area of this figure? Use 3.14 for pi.

andrey2020 [161]

Answer:

24,53cm²

Step-by-step explanation:

rectangle area=length×width=7×3

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3 years ago

Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premiu

AnnZ [28]

Premium rates are usually for premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202

<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
Thus, we have p = 6.01, y = 1000

Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

$\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun$