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jek_recluse [69]
4 years ago
8

I need help assap !!!!

Mathematics
2 answers:
tatiyna4 years ago
8 0

Answer:

C & D

Step-by-step explanation:

Both have an odd amount of numbers, meaning there is a perfect middle.

murzikaleks [220]4 years ago
5 0

Answer:

it is c and d so i awnsered late hope this helps

Step-by-step explanation:

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3 years ago
Question 4 <br> Use the figure below to find the value of x and y
Tpy6a [65]

Answer:

x=4, y=8

Step-by-step explanation:

step 1

Find the value of y

we know that

In the right triangle of the figure

cos(30\°)=\frac{4\sqrt{3}}{y}

Remember that

cos(30\°)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=\frac{4\sqrt{3}}{y}

Simplify

y=8\ units

step 2

Find the value of x

In the right triangle of the figure

sin(30\°)=\frac{x}{8}

Remember that

sin(30\°)=\frac{1}{2}

so

\frac{1}{2}=\frac{x}{8}

x=4\ units

4 0
3 years ago
Prudence has 12 pairs of gold earrings and 12 pairs of silver earrings in a drawer in her jewelry box. If she randomly pulls six
Gnom [1K]
I think D 3 bc the ratio is 12:12
7 0
3 years ago
Consider a geometric sequence with a first term of 4 and a fourth term of -2.916.
Orlov [11]

Answer:

a) Find the common ratio of this sequence.

Answer: -0.82

b) Find the sum to infinity of this sequence.

Answer: 2.2

Step-by-step explanation:

nth term in geometric series is given by 4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82

where

a is the first term

r is the common ratio and

n is the nth term

_________________________________

given

a = 4

4th term = -2.196

let

common ratio of this sequence. be r

4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82

a) Find the common ratio of this sequence.

answer: -0.82

sum of infinity of geometric sequence is given by = a/(1-r)

thus,

sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2

4 0
3 years ago
What is the least common multiple of 9 and 8
leonid [27]

Answer:

72 is the least common multiple

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3 years ago
Read 2 more answers
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