Answer:
The length of a rectangle is 2 feet more than it's width. How do you find the dimensions of the rectangle if its area is 63 square feet?
Step-by-step explanation:
x(x+2) = 63
x^2 + 2x = 63
x^2 + 2x - 63 = 0
Quadratic formula with numbers plugged in: (-2 +or- sqrt(4 - 4* 1 * -63))/2 becomes
-2 +or- sqrt(256)/2 so (-2 +or- 16)/2 therefore -18/2 or 14/2. Discard negative result.
x = 7. 63/7=9. Sides are 7ft and 9ft.
Answer:
2/4 and 1/2
Step-by-step explanation:
I'm not sure if this is what you meant? i hope this helps anyway though!
8.75 x 37.5= ? Well all you do is have to line up the decimals and work it out! :) it's simple
Answer:
0
Step-by-step explanation:
Using the trigonometric identity
cotx = 
Given
3cotθ = 2 , then
3
= 2 ( multiply both sides by sinθ )
3cosθ = 2sinθ ( subtract 3cosθ from both sides )
2sinθ - 3cosθ = 0
Thus

= 
= 0
Answer:
C
Step-by-step explanation:
it is defined for all real numbers.