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Alina [70]
3 years ago
13

Divide 36 in to the ratio 2 : 3 :1

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

the ans is 0.5

(hope it helps :D hehe)

Step-by-step explanation:

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Fill in the blank. given e below, you can conclude that is congruent to ___________.
Orlov [11]
Is there a picture that would help me so I can help you? Thanks
3 0
4 years ago
In the New Orleans metropolitan area in August​ 2005, the labor force was​ 634,512 and​ 35,222 people were unemployed. In Septem
Lisa [10]

Answer:

 Unemployment (August) = 35'222/634'512 ≈ 0.0555 ≈ 5.55%

Employed (August) = 634'512-35'222 = 599'290

Labor force (September) = 634'512-156'518 = 477'994

Employed (September) = 599'290-206'024 = 393'266

Unemployed (September) = 477'994-393'266 = 84'728

Unemployment (September) = 84'728/477'994 ≈ 0.177 ≈ 17.7%

Step-by-step explanation:

8 0
3 years ago
The question is in the screenshot.
Musya8 [376]

Answer:

v = 4

Step-by-step explanation:

<em>u + at = v</em>

a (-2) multiplied by t (3) = -6

-6 + u (10) = 4

5 0
3 years ago
Read 2 more answers
Expreess 3.81 as a mixed number
Luba_88 [7]

Answer:

3.81 = 3 81/100

Step-by-step explanation:

This can’t be simplified so it stays as 3 \frac{81}{100}

8 0
3 years ago
13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas
Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

5+5^{2}=30 (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

5^{1}+5^{2}+5^{3}+...+5^{x}>19000 (II)

Buscamos el valor de x que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000

19530>19000

El valor de x que satisface (II) es x=6.

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro x=6, el número de horas que pasaron son 5 horas (1 menos que el valor de x)

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0
4 years ago
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