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Otrada [13]
4 years ago
7

Joaquin is constructing the perpendicular bisector of AB. What should be his

Mathematics
1 answer:
Licemer1 [7]4 years ago
4 0
The correct answer is C
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Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three
irinina [24]

Answer:

  7/3

Step-by-step explanation:

The distances have the ratio ...

  (Q -P) = (2/3)(R -P)

  Q = P +(2/3)R -(2/3)P = (2R +P)/3

  Qy = (2Ry +Py)/3 = (2·0 +7)/3 = 7/3

8 0
3 years ago
Its for a test and its urgent please help :)
geniusboy [140]

Answer:

<h2>34</h2><h2 />

Step-by-step explanation:

| 2 - 4a | - 2(b - 7)

let a = 3, b = -5

substitute a = 3, b = -5 into the equation:

| 2 - 4a | - 2(b - 7)

= | 2 - 4(3) | - 2(-5 - 7)

= | 2 - 12 | - 2(-12)

= | -10 | + 24

= 10 + 24

= 34

3 0
3 years ago
Verify:x³+Y³=(x+y)(x²-xy+y²)
Karolina [17]
RHS-
(x+y)(x²-xy+y²)
=x(x²-xy+y²)+y(x²-xy+y²)
=x³-x²y+xy²+x²y-xy²+y³
(CANCEL THE POSSIBLE TERMS)
=x³+y³
=LHS
therefore verified
7 0
4 years ago
It is given that f(x) = 2x2 - 12x + 10.
Furkat [3]

Answer:

a = 2, b = - 3, c = - 8

Step-by-step explanation:

Expand f(x) = a(x + b)² + c and compare coefficients of like terms, that is

a(x + b)² + c ← expand (x + b)² using FOIL

= a(x² + 2bx + b²) + c ← distribute parenthesis by a

= ax² + 2abx + ab² + c

Compare like terms with f(x) = 2x² - 12x + 10

Compare coefficients x² term

a = 2

Compare coefficients of x- term

2ab = - 12, substitute a = 2

2(2)b = - 12

4b = - 12 ( divide both sides by 4 )

b = - 3

Compare constant term

ab² + c = 10 , substitute a = 2, b = - 3

2(- 3)² + c = 10

18 + c = 10 ( subtract 18 from both sides )

c = - 8

Then a = 2, b = - 3, c = - 8

 

8 0
4 years ago
Find the decimal that is equivalent to: 4/11
bezimeni [28]

Answer:

0.3636 repeating

Step-by-step explanation:

When you divide them, it is 0.36363636 going on forever.

7 0
3 years ago
Read 2 more answers
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