Use the explicit rule to find the 22nd term of the sequen e 5,8.11
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The fractions you use must be the correct conversion factors.
1 km = 1000 m, so you can have the fraction (1 km)/(1000 m) or the fraction (1000 m)//(1 km). You must choose the correct one for this problem.
1 hr = 60 min, so you can have the fraction (1 hr)/(60 min) or the fraction (60 min)/(1 hr). Again, you must choose the correct one for this problem.
The important thing is to choose the correct fraction from the choices.
How do you know which conversion fractions to use?
You look at the given units and the units you want.
You must pick the conversion fraction that will cancel out the units you DON'T want, leaving the units you want.
You have a speed in km/hr.
km is in the numerator. To cancel out km, you must pick the conversion fraction that km in the denominator.
hr is in the denominator. To cancel out hr, you must pick the fraction that has hr in the numerator.
Notice that km and km cancel out leaving m.
Also, hr and hr cancel out leaving min.
1 km = 1000 m, so you can have the fraction (1 km)/(1000 m) or the fraction (1000 m)//(1 km). You must choose the correct one for this problem.
1 hr = 60 min, so you can have the fraction (1 hr)/(60 min) or the fraction (60 min)/(1 hr). Again, you must choose the correct one for this problem.
The important thing is to choose the correct fraction from the choices.
How do you know which conversion fractions to use?
You look at the given units and the units you want.
You must pick the conversion fraction that will cancel out the units you DON'T want, leaving the units you want.
You have a speed in km/hr.
km is in the numerator. To cancel out km, you must pick the conversion fraction that km in the denominator.
hr is in the denominator. To cancel out hr, you must pick the fraction that has hr in the numerator.
Notice that km and km cancel out leaving m.
Also, hr and hr cancel out leaving min.