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Mariana [72]
3 years ago
7

Use the explicit rule to find the 22nd term of the sequen e 5,8.11

Mathematics
1 answer:
liubo4ka [24]3 years ago
4 0

Answer:

68

Step-by-step explanation:

The first differences of the given terms are ...

8 -5 = 3

11 -8 = 3

These are the same value, so we see this sequence is an arithmetic sequence with a common difference of 3. The first term is 5.

The explicit formula for the n-th term is ...

an = a1 +d(n -1)

We know a1=5, d=3, and we want to find the value for n=22. Hence ...

a22 = 5 +3(22 -1) = 5 +63 = 68

The 22nd term is 68.

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Find the exact value of each trigonometric function for the given angle θ.
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Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

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garri49 [273]

Answer:

g(r) = 18

Step-by-step explanation:

Substitute 10 into r

g(10) = 2( (10) -1)

        = 2(9)

        = 18

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Answer: 10

Step-by-step explanation:

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I'd have to say it's A. Please don't blame me if I'm wrong. :)

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The answer is C

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