HSO3 acts as the reducing agent.
IO3 acts as the oxidizing agent.
The skeleton equation representing the formation of I2 from I03 and HSO3 is as follows:
IO3(aq) + HSO3 (aq)-------> HSO4(aq) + SO4 (aq) + H₂O(l) + I2 (s)
Assign the oxidation number to each and every species involved in the above reaction to identify the oxidizing agent and reducing agent.
IO3(aq) + HSO3 (aq)-------> HSO4(aq) + SO4 (aq) + H₂O(l) + I2 (s)
(+5)( -2) (+1)(+4)(-2) (+1 )(6) (-2 ) (+6)(-2) (+1)(-2) (0)
Oxidation process involves the increase in the oxidation number whereas the reduction process involves the decrease in the oxidation number. Since the oxidation number of sulfur increases from +4 to +6, sulfur metal is oxidized from HSO3 to SO4.
Thus, HSO3 acts as the reducing agent.
Since the oxidation number of iodine is decreased from +5 to 0, iodine reduced from IO3 to I2.
Thus, IO3 acts as the oxidizing agent.
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