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3 years ago

The percentage of oxygen by mass in water is greatest when

Chemistry

1 answer:

ss7ja [257]3 years ago

4 0

We know, by law of constant proportion :

Chemical compounds always contains its component in constant fixed ratio or in fixed percentage without depend on its source, method of preparation and mass of compound.

Therefore, percentage of oxygen is same for any mass.

Hence, this is the required solution.

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bekas [8.4K]

Answer:

high ph -basic,low pH -acidic

Explanation:

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5 0

3 years ago

An atom of sodium can transfer its one valence electron to an atom of

Jet001 [13]

Answer: O fluorine to complete the octet rule

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6 0

3 years ago

What would be the best product to neutralize battery acid

Anna [14]

Answer:

Baking Soda a base

Explanation:

We know that to neutralize an acid we add base to it. Baking Soda is a type of base so when we add Baking Soda or any other base to battery acid or any other acid we can neutralize it and get salt and water.

Acids are the substance which are sour in taste and can turn blue litmus paper red. For example, Lemon and Orange.

Bases are the substance which are bitter in taste and can turn red litmus paper blue. For example, Baking Soda and Soap.

7 0

2 years ago

1) Define water gas<br>2) The skuLL is divided into two parts name them

Triss [41]

• a fuel gas consisting mainly of carbon monoxide and hydrogen, made by passing steam over incandescent coke

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5 0

2 years ago

When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t

satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

$Q=C\times Delta T$

$Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J$

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = $\frac{15.3 g}{85 g/mol}=0.18 mol$

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

$\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ$

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0

3 years ago