There are 2 moles of O stones present in 88 grams of CO2. Why? Well, we can find the amount of moles present in 88 grams of CO2 by dividing the mass by the molar mass. The mass of CO2 comes out to be 88 grams. The molar mass of CO2 comes out to be 44 grams. Because 88 is the mass of CO2 and 44 is the molar mass of CO2, we can divide 88 by 44 to identify that there are 2.0 moles of O atoms present in 88 grams of CO2.
Your final answer: There are 2.0 moles of O atoms present in 88 grams of CO2. Your final answer to this question is D, or 2.0 moles. If you need to better understand, let me know and I will gladly assist you.
One difference is that some animals are polyp and some are medusa.
The other difference is that some animals have medusa in their life or polp in their life cycle.
Hope these two differences helps :D
Answer:
42.38875878%
Explanation:
i divided 4.27 g from 1.81g using a percentage calculator but im not sure if its correct
Answer: The percent yield of the reaction is 77.0 %
Explanation:
According to stoichiometry:
2 moles of 
produces = 2 moles of 
2.18 moles of is produced by=
of
Mass of =
percent yield =
When you burn a log in your fireplace you are converting c<span>ellulose into carbon dioxide and water.
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Wood is made from cellulose. When wood burns, cellulose reacts with oxygen from the air and it forms carbon dioxide and water vapor.
The reaction of the combustion of glucose is as follows:
C₆H₁₂O₆ + 6O₂ = 6 CO₂ + 6H₂O
When wood burns, we notice that it slowly disappears because it passes into the mentioned gases. The ash that is created is part of the wood that did not burn.
