Answer:
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
Explanation:
Step 1: Data given
For the reaction aA + bB ⇆ cC + dD
the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a
Step 2: The balanced equation
Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g)
Step 3: Calculate the equilibrium constant Kc
Kc = [C]^c * [D]^d/[B]^b*[A]^a
⇒with [C] = [Fe]
⇒ with c = 2
⇒with [D] = [H2O]
⇒with d = 3
⇒with [A] = [Fe2O3]
⇒with a = 1
⇒with [B] = [H2]
⇒with b = 3
Kc = [C]^c * [D]^d/[B]^b*[A]^a
Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
Answer:
D. 12
Explanation:
The pH is a measure of the acidity of a solution. The pH indicates the concentration of hydronium ions [H3O +] present in a solution;
pH = - log [H3O+]
So
pH= - log [7.8 × 10−13 M]
finally
pH= 12
Answer:
2. All the naturally occurring isotopes of Mg.
Explanation:
You want to know the atomic mass of the magnesium you use in the lab. That’s “natural” magnesium. So, you must use the weighted average of all the naturally occurring isotopes in natural Mg.
1. and 3. are <em>wrong</em>. You won’t get the correct mass for natural Mg if you use only the artificial isotopes for your calculation.
4. is <em>wrong</em>. You must use all the naturally occurring isotopes. The two most abundant isotopes of Mg account for only 90 % of the atoms. If you ignore the other 10 %, your calculation will be wrong.
You can use the formula: C = k - 273 to solve this problem. C stands for Celsius, and k stands for kelvin. Given the information that the Kelvin is 172k, then you can plug it into the equation and get C = (172) - 273. The correct melting point in C is -101°C. Hope this helped!
Answer is: .408,5 J.m(C₆H₆-benzene) = 39 g.
n(C₆H₆) = m(C₆H₆) / M(C₆H₆) = 39g ÷ 78g/mol = 0,5 mol.ΔT = 10,0°C, difference at temperature.c(benzene) = 81,7 J/mol·°C, specific heat of benzene.Q = n(benzene) · ΔT · c(benzene), heat of reaction.Q = 0,5 mol · 10,0°C · 81,7 J/mol·°C.Q = 408,5 J.
