FH←→ is tangent to circle E at point F.
2 answers:
Answer: SECOND OPTION.
Step-by-step explanation:
It is important to remember that a tangent to a circle is a line that touches it at one point. This point is called "Point of tangency". By definition, the angle between the tangent and the radius is 90 degrees.
In this case you can observe that EF is the radius of this circle, therefore, the angle between EF and FH measures 90 degrees.
Based on this, you can say the following:
This matches with the second option.
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Answer:
Range of is (−5,11).
Step-by-step explanation:
Given the invertible function Ф(x) which has the domain (−5,11) and the range (−12,1).
Invertible function is the function that inverses another function i.e if y=Ф(x) then x=g(y) where g is called the inverse of Ф and denoted by
Given Ф(x) the function whose domain is (−5,11) and range is (−12,1). Therefore, by definition of invertible function there exist a function g with domain (−12,1) and range (−5,11) which is called the inverse function denoted by
Hence, Range of is (−5,11)