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vlabodo [156]
3 years ago
13

Suppose the invertible function φ(x) has the domain (−5,11) and the range (−12,1).

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
5 0
<h2>Answer:</h2>

The range of  φ^−1(x) is: (-5,11)

<h2>Step-by-step explanation:</h2>

We know that for any given function f(x) with the given domain and range.

If the function is invertible then the domain and range of the function and it's inverse get's interchanged.

i.e. the domain of the function is the range of it's inverse and the range of the function is the domain of it's inverse.

Here we have a invertible function φ(x) such that it has the domain (−5,11) and the range (−12,1).

This means that the range of it's inverse is: (-5,11)

Rom4ik [11]3 years ago
3 0

Answer:

Range of \phi^{-1} is (−5,11).

Step-by-step explanation:

Given the invertible function Ф(x) which has the domain (−5,11) and the range (−12,1).

Invertible function is the function that inverses another function i.e if y=Ф(x) then x=g(y) where g is called the inverse of Ф and denoted by\phi^{-1}

Given Ф(x) the function whose domain is (−5,11) and range is (−12,1). Therefore, by definition of invertible function there exist a function g with domain (−12,1) and range (−5,11) which is called the inverse function denoted by \phi^{-1}

Hence, Range of \phi^{-1} is (−5,11)



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The circle below has center k , and its radius is 3 cm Given that m∠LKM =70° , find the length of the major arcLNM
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The length of the major arc LNM is \frac{29}{6}\pi \ cm

<h3><u>Length of an arc</u></h3>

From the question,

We are to determine the value of the length of the major arc LNM

The length of the major arc LNM can be calculated using the formula

Length \ of \ major\ arc \ LNM = \frac{Reflex \

Where r is the radius

First, we will determine the value of the reflex ∠LKM

Reflex ∠LKM + ∠LKM = 360° (<em>Sum of angles at a point</em>)

From the given information,

∠LKM = 70°

Then,

Reflex ∠LKM + 70° = 360°

Reflex ∠LKM = 360° - 70°

Reflex ∠LKM = 290°

Also, from the question

r = 3 cm

Now, putting the parameters into the formula, we get

Length \ of \ major\ arc \ LNM = \frac{290 ^\circ }{360 ^\circ} \times 2\pi \times 3

Then,

Length \ of \ major\ arc \ LNM = \frac{1740\pi}{360}

Length \ of \ major\ arc \ LNM = \frac{29}{6} \pi \ cm

Hence, the length of the major arc LNM is \frac{29}{6}\pi \ cm

Learn more on calculating length of an arc here: brainly.com/question/2005046

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