All categories

4 years ago

What are the four (4) major types of medical wasted?

1 answer:

6 0

General waste - medical waste that does not pose any harmful threats
Hazardous waste - medical waste that can be harmful but does not pose a risk to infection
Infectious waste - medical waste materials that poses risk of infection to humans
Radioactive waste - medical waste that contains radioactive material

You might be interested in

A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 33 hours, 50 mg of the substa

Hoochie [10]

Answer:

$m\approx34.99$

Explanation:

Radioactive decay behaves according to the law of exponential decay:

$m(t)=m_0*e^{-rt}$

Where:

$r=Decay\hspace{3}rate$

$t=Time(In\hspace{3}days)$

$m_0=Initial\hspace{3}amount\hspace{3}of\hspace{3}substance$

$m(t)=Amount\hspace{3}of\hspace{3}substance\hspace{3}at\hspace{3}time\hspace{3}t$

So we need to find the decay rate r. Let's find it using the equation and the data provide, but first, we need to convert the hours in days:

$50h*\frac{1day}{24h}=\frac{25}{12}day\\ 33h*\frac{1day}{24h} =\frac{11}{8}day$

Now for $t=\frac{11}{8},m=50$ then:

$m(\frac{11}{8} )=100*e^{-r(\frac{11}{8}) } =50$

Divide both sides by 100:

$e^{-r(\frac{11}{8}) } =\frac{1}{2}$

Take the natural logarithm of both sides:

$-\frac{11}{8}x=ln(\frac{1}{2} )$

Multiply both sides by -8/11:

$x=\frac{-8ln(\frac{1}{2} )}{11} \approx0.504107$

Now we have found the rate decay r, let's find how many milligrams will remain after 59 hours (25/12 day):

$m(\frac{25}{12} )=100*e^{-0.504107*\frac{25}{12}) } =100*e^{-1.050222917}=34.98597508\approx35.99$

4 0

3 years ago

Which is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA?

astra-53 [7]

Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

8 0

3 years ago

a) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy sou

lina2011 [118]

Charge me and do I name for meters

3 0

3 years ago

A negatively charged rod is brought near a neutral metal sphere. Which of the following is true? A negatively charged rod is bro

Yuki888 [10]

Answer:

There is an attractive force between the rod and sphere.

Explanation:

When negatively charged rod is placed close to the metal sphere then due to the electric field of the rod the opposite free charge of metal sphere comes closer to the rod on one surface

While similar charge in the metal sphere move away from the rod due to repulsion of electric field of rod

This temporary charge distribution of the metal sphere is known as induction

And since opposite charge on the metal surface comes closer to the metal sphere so here we can say that the rod will attract the metal sphere

so here correct answer will be

There is an attractive force between the rod and sphere.

3 0

3 years ago

Read 2 more answers

According to the third law of planetary motion, the period of revolution of a planet is related to the planet’s _____.

matrenka [14]

Distance from the sun.

The third law of planetary motion states that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit. The semi-major axis is the distance from the sun to the epicenter of the ellipse (which would be the planet in question). So, the revolutionary period is directly related to the distance of the planet from the sun.

7 0

3 years ago

Read 2 more answers