Answer:
I = 11.26 mA
Explanation:
given,
V = 0.7 V length = 80 m
diameter = 0.2 mm = 0.02 cm
radius = 0.01 × 10⁻² m
ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C
A = cross sectional area = π r² = π (0.01 × 10⁻² )²
= 31.4× 10⁻⁹ m²
R = 62.165 Ω
I = 11.26 mA
By Bernoulli Theorem, We know, that for any two points in the pipe, total energy would be same.
Pressure Energy + K.E. of 1st pipe = Pressure Energy + K.E. of 2nd pipe
[ No need to consider Potential energy as height isn't mentioned]
P₁ + mv₁²/2 = P₂ + mv₂²/2
So, we know, P + mv²/2 = constant
As value of kinetic energy is larger in larger in 2 in. pipe [ 'cause area is indirectly proportional to velocity ], Value of pressure energy would be smaller in it. So, pressure energy will be higher in the pipe of 3 in.
In short, option A would be your correct answer.
Hope this helps!
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