The figure below shows a shaded rectangular region inside a large rectangle:
2 answers:
First we need to find the areas of both rectangles.
And area of larger rectangle = 10*5=50 square units
Area of smaller rectangle = 7*3 = 21 square units
Area between the two rectangles, = 50-21=29 square units
And since, we have to find the probability that a point is choosen is not in the shaded rectangle that is the smaller rectangle, so it means we have to find the probability of the point is choosen in the area between the two rectangles . Therefore,
Required probability =
Therefore correct option is the second option .
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600*1,25$=750$
Answer:
a i.) The mean for the security company is $ 1.47 million
a ii.) The median for the security company is $ 1.55 million
a iii.) The mean for the other companies is $ 1.96 million.
a iv.) The mean for the other companies is $ 2.0 million.
b) B. The mean and the median for the security company are both lower than the mean and the median for the collections performed by other companies.
c) B. Since the security company appears to have collected lower revenue than the other companies, there is some evidence of stealing by the security company's employees.
Step-by-step explanation:
By mean, we sum all the observation and divide by the sample size (n). Where sample size is the number of observations.
Mathematically,
, where xi is the observations or values given.
By median, we mean middle number. So, we sort the values in ascending or descending order and take the value(s) in the middle. If the sample size is even, we take the 2 middle values and obtain the average.
See below, R programming codes for the solution.
##########...... R code
s = c(1.6,1.8,1.6,1.8,1.7,1.2,1.1,1.2,1.2,1.5)
c = c(1.5,2.1,1.9,2.2,1.9,1.7,2.1,2.2,2.2,1.8)
length(s)
mean(s); median(s)
mean(c);median(c)
t = (mean(s)-mean(c))/sqrt((var(s) + var(c))/length(s))
pnorm(t)
##############################################
For question C, we compute the test statistics, and obtain the p-value, see the last two lines of the R codes.
And since the p-value is less than level of significance, the test is significant. Thus, we conclude that:
<em>Since the security company appears to have collected lower revenue than the other companies, there is some evidence of stealing by the security company's employees.</em>