3 years ago

Find the area of the isosceles trapezoid. leave your answer in simplest radical form 4cm 7cm 3cm

1 answer:

8 0

The area of a trapezoid is (a+b)/2 * h
a is the length of the small base which is the one on the top and is 4cm
b is the length of the big base which is the one at the bottom and is 4 + 3 + 3 = 10cm
h is the height which is 7cm
So the area is (4+10)/2 * 7
A= 14/2 * 7
A= 7 * 7
A= 49 cm^2

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Answer:

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Step-by-step explanation:

We have the function $f(x)=2(x)^2+5\sqrt{(x+2)}$

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

$f(0)=2(0)^2+5\sqrt{(0+2)}$

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$f(0)=5\sqrt{(2)}$

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