Answer:
The minimum amount of breaking strain the crane can handle is 6350 kg. (Since it is measured to 2 sig. figs, 6349 kg would round down to 6300 kg, hence the min. is 6350 kg.)
The maximum weight of each crate would be 94 kg. (Since it is measured to the nearest 10 kg, 95 kg would round up to 100 kg, hence the max. is 94 kg.)
Therefore, the greatest number of crates that can be safely lifted would be (6350/94) crates which is 67.5 crates, which rounded down is 67 crates.
All numbers are taken as integers in this answer.
Step-by-step explanation:
Hope this helped!
-.77777778 or simply just -.77
As your testing H0:p=0.79, then you have a two-tailed test.
The p-value at two-tailed test is given by:
Then, you need to check into the standard normal cumulative table to find at which -z you do have a probability of 0.395. Thus:
As you can see in the picture at z=-0.26 you have a P(Z<=-z)=0.3974
And at z=-0.27 you have a P(Z<=-z)=0.3936.
The average of these values is:
Then, you have a probability of 0.395 at a z of:
Then -z=-0.27, thus z=0.27
You can make 8 triangles from this shape.
It would be 25 because if F(x)=25 just plug 25 into X and you have X
I hope this right if not let me know hope I helped and didn't srew u up good luck
