Answer:
I would say parallelogram. So the rectangle still fits but more shapes can be applied.
7(a - 10) = 13 - 2(2a + 3)
7a - 70 = 13 - 4a - 6 = 7 - 4a
7a + 4a = 7 + 70
11a = 77
a = 77/11 = 7
a = 7.
To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.
Let's plug it into the first equation first:
-2(3) - 4(-2) might = 2
-6 + 8 = 2
The first equation is true.
Now, we need to check the second equation:
3(3) + 4(-2) might =8
9 - 8 does not = 8
Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.
Hope this helps!
I'll give you a few hints. Area of a rectangle is length times width. We know that length times width is 135 sq ft, so we can express it as:
<span>L * W = 135 </span>
<span>Now, L is 6 feet longer than width (L = 6 + W). Something tells me this is going to involve a quadratic formula then plugging in values into our original equation. </span>
