Answer:
9b) -8 = y
9a) 72° = <em>m</em>∠<em>ABC</em>
Step-by-step explanation:
Since you have an angle trisector, in this case, <em>m</em>∠<em>CBE</em><em> </em>≅ <em>m</em>∠<em>DBA,</em><em> </em>therefore you <em>set</em><em> </em><em>x</em><em> </em>equal to 8, plus, according to Morley's Trisector Theorem, all three angles form an equilateral triangle, so <em>m</em>∠<em>BOC</em><em> </em>also has to equal 24°:
Then, <em>m</em>∠<em>ABC</em><em> </em>comes from multiplying 3 by 24 [three <em>twenty-</em><em>four</em>'s], which results in 72°.
I am joyous to assist you anytime.
You line up the decimal points so that similar place values are lined up. it will be easier to add them.
Answer:
x=-4/3
Step-by-step explanation:
x -4x-1=3
-3x-1=3
-3x-1+1=3+1
-3x=4
-3x/3 = 4/-3
x=-4/3
I hope this helps!
Answer:
6u
Step-by-step explanation:
The two terms 10u and 4u are like terms because they both carry the same variable (u) with the same degree (1). So, we can just subtract them as if they were normal numbers 10 - 4:
10u - 4u = 6u
Thus, the answer is 6u.
Hope this helps!
Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
