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marishachu [46]
3 years ago
13

Which methods could you use to calculate th y-coordinate of the midpoint of a vertical line segment with ndpoints at (0,0) and (

0,-12)? check all that apply
A. divide -12 by 2
B. count by hand
C. divide 12 by 2
D. Add the endpoints
Mathematics
1 answer:
Damm [24]3 years ago
3 0
Answer: B count by hand
Explaining:
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In the parrallelogram, find y.
Nutka1998 [239]

Answer: I think it’s b which is also 5

Step-by-step explanation:

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The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is Your answer: {−1, 1, 3} {−1, −1, 1, 3} {−4, −2, 2,
nalin [4]

Answer:

The range is all the y values.

Therefore, the range is : {-4,-2,2}.....I realize choice c has all the y values listed, however, if u have repeating y values, u only have to list it once.

Step-by-step explanation:

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BlackZzzverrR [31]

Answer:

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The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
Suppose there is a bag of 10 marbles. Of the 10 marbles, 5 are blue, 3 are green, and 2
harina [27]

Answer:

27/1000

Step-by-step explanation:

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