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Fantom [35]
3 years ago
7

Where can you place CSS statements in an HTML file?

Computers and Technology
1 answer:
aksik [14]3 years ago
3 0

Answer:

The CSS file is loaded in a separate folder in a web application,  and finally the classes, ids and tag type mentioned in the CSS file, and how we style them in the file styles those parts of a web page, or an html page. And CSS statements can be mentioned like below:

<tag id="q1" style="CSS Statement"></tag>

As an example,

<h1 id="q1" style="font-size:12;font-family:helvetica;">The Web Page</h1>

Explanation:

Please check the answer section.

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What are the four major software packages of microsoft​
Reika [66]

Answer:

» Microsoft word ( word processing )

» Microsoft powerpoint ( presentation )

» Microsoft access ( database mamagement )

» Microsoft excel ( spread sheets )

Explanation:

.

3 0
3 years ago
Write a Java program in jGRASP that creates a 2D integer array of 5 rows and 20 columns, fills it with increasing integer values
Alex73 [517]

Answer:

As per the question we need to make 5 rowa and 2o columns, in this we have total element 100 so range should be 0 to 99, but we are suggested to keep range 0 to 59, so i have kept the elementns in the range, but if it was a typo in the question for range you do not need to reset the k with zero.

Explanation:

//create a new class  TestArray

public class TestArray {

//define main method

public static void main(String[] args) {

 //declare a 2D array of given size i.e. 5 rows and 20 columns

 int arr[][] = new int[5][20];

 //declare an integer variable k and initialize it with zero, this will used to initialize the array from 0 to 99

 int k = 0;

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //initialize arr with the current value of k

   arr[i][j] = k;

   //once k is 59 set it zero again as we are not going beyond 59

   if(k == 59)

    k = 0;

   //increment value of k with 1

   k++;

  }

 }

 //print the element from the array one by one

 //for loop for rows

 for (int i = 0; i < 5; i++) {

  //for loop for columns

  for (int j = 0; j < 20; j++) {

   //print the current element of array and an space with it

   System.out.print(arr[i][j]+" ");

  }

  // move the cursor to new line

  System.out.println();

 }

}

}

7 0
4 years ago
A client contacted you to request your help in researching and supplying the hardware necessary to implement a SOHO solution at
erastova [34]

Answer:

The correct answer to the following question will be "DHCP server".

Explanation:

A network manager that dynamically supplies and delegates equipment of clients with their IP addresses, standard portals and some other networking specifications, known as DHCP server.

  • It depends on the standard operating procedure classified as Dynamic Host Configuration Protocol to answer to client-specific broadcasting commands.
  • It's used to optimize the authentication mechanism of computers on IP channels, enabling them using applications and services including NTP, DNS, and any UDP or TCP-based networking protocol.

Therefore, the DHCP server is the right answer.

7 0
3 years ago
It takes you 0.8 of a minute to read each page of your health book. It takes you 5.5 minutes to take the test at the end. How lo
NeTakaya
The answer would be 13.3125 because 6.25 / 0.8 is 7.8125 than add 5.5 which will equal 13.3125. I'm sure about this.
7 0
3 years ago
Read 2 more answers
Can someone explain to me how to do circuit calculations
GenaCL600 [577]

Use the following rules:

- The sum of currents that enter and exit a node (junction) is always zero. So if you have 3 wires that connect, through one flows 2A, the other 3A, then the third must deliver 5A (taking the direction into account!)


- The sum of voltages across different components should always add up. So if you have a battery of 10V with two unknown resistors, and over one of the resistors is 4V, you know the other one has the remaining 6V.


- With resistors, V=I*R must hold.

With these basic rules you should get a long way!

7 0
3 years ago
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