Question

Write an equation of a line in slope intecept form that has a slope of 3/4 and passes through (-6,8)

Answer 1

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{8})~\hspace{10em} slope = m\implies \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-8=\cfrac{3}{4}[x-(-6)]\implies y-8=\cfrac{3}{4}(x+6) \\\\\\ y-8=\cfrac{3}{4}x+\cfrac{9}{2}\implies y=\cfrac{3}{4}x+\cfrac{9}{2}+8\implies y=\cfrac{3}{4}x+\cfrac{25}{2}$