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2 years ago

Because of the commutative property of multiplication, it is true that

Mathematics

1 answer:

Likurg_2 [28]2 years ago

4 0

Answer:

1. 3/4 + 3/4 + 3/4 +3/4

2. 0.75 * 4

Step-by-step explanation:

1. add 3/4 four times

3/4 + 3/4 + 3/4 +3/4

2. You can turn 3/4 into a decimal. 3/4 =0.75

0.75 * 4

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(2,-1) y-intercept -3 slope 1/2 Write an equation with the given info above.

jek_recluse [69]

y-intercept -3

slope 1/2

is sufficient info with which to write an equation for a straight line:

y = mx + b becomes y = (1/2)x - 3.

You should check this by determining whether or not (2,-1) satisfies this equation.

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2 years ago

Simplify square root 3y diviede by square root of y

Nataly [62]

Answer:

Step-by-step explanation:

√3y/√y

= √(3y/y)

= √3

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2 years ago

what does it mean to write each power as a product of factors .for example 3 to the 3rd power. does it mean like 3×3×3=27 or 43

Luda [366]

It Means 3×3×3=27 . The First Option Is Correct

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2 years ago

In a bag, there is equal number of red, blue and yellow marbles. How many marbles could be in the bag?

valentinak56 [21]

Answer:

there are 30

Step-by-step explanation:

10 in each bag

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1 year ago

WILL GIVE BRAINIEST IF DONE IN 10 MINUTES!!!!!

Mama L [17]

Answer:

$\sin(\theta)=-12/13\text{ and } \csc(\theta)=-13/12\\\cos(\theta)=-5/13\text{ and } \sec(\theta)=-13/5\\\tan(\theta)=12/5\text{ and } \cot(\theta)=5/12$

Step-by-step explanation:

So we know that:

$\sin(\theta)=-12/13\text{ and } \sec(\theta)$

This tells us that our angle θ is in Quadrant III. This is because, recall ASTC. In QI, everything is positive. This is not the case here since sine and secant are both negative.

In QII, only sine is positive. Since sine is negative, θ can't be in QII.

In QIII, only tangent (and cotangent) is positive. All other are negative. So, θ is in QIII.

And just to check, in QIV, only cosine (and secant) is positive. Since we are told that secant is less than 0 (in other words, negative), θ can't be in QIV.

Now that we know that θ is in QIII, we know that sine and cosecant is negative; cosine and secant is negative; and tangent and cotangent is positive.

Now, let's find the ratios. Remember what sine tells us. Sine gives us the ratio of the opposite side to the hypotenuse. With this information, let's find the adjacent side:

So, the opposite is 12 (ignore the negative for now) and the hypotenuse is 13. Therefore, we can use the Pythagorean Theorem:

$a^2+b^2=c^2$

Substitute 12 for a and 13 for c:

$12^2+b^2=c^2$

Now, solve for b to find the adjacent side. Square the values:

$144+b^2=169$

Subtract 144 from both sides:

$b^2=25$

Square root:

$b=\pm 5$

We can ignore the negative and just take the positive. While the answer is technically -5, we don't need to do that. So, our adjacent side is 5.

Therefore, with respect to angle θ, our opposite is 12, our adjacent is 5, and our hypotenuse is 13. With this, we can compute the other trig ratios. Let's start with the 3 main ones:

Sine:

$\sin(\theta)$