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3 years ago

Which pair of fractions is equivalent to this pair:

tle="\frac{3}{5}" alt="\frac{3}{5}" align="absmiddle" class="latex-formula"> and $\frac{2}{7}$
A: $\frac{7}{35}$ and $\frac{5}{35}$
B: $\frac{21}{35}$ and $\frac{10}{35}$
C: $\frac{24}{35}$ and $\frac{12}{35}$
D: $\frac{10}{35}$ and $\frac{7}{35}$

Mathematics

1 answer:

liubo4ka [24]3 years ago

4 0

$\dfrac{3}{5}=\dfrac{3\cdot7}{5\cdot7}=\dfrac{21}{35}\\\\\dfrac{2}{7}=\dfrac{2\cdot5}{7\cdot5}=\dfrac{10}{35}\\\\Answer:\ \boxed{B.}$

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Let "h" be the height of container

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Therefore,

width = height - 5

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$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

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