The answers are a.) 0.03 mol KOH requires 0.03 mol HCl, b.) 2 mol NH3 requires 2 mol HCl and c.) 0.1 mol Ca(OH)2 requires 0.2 mol HCl.
Solution:
We need to write the balanced equations for each reactions to find out the stoichiometry for each reactants.
a.) HCl (aq) + KOH (aq) → KCl (aq) + H2O(ℓ)
From the balanced equations, we can see that 1 HCl reacts with 1 KOH, therefore if 0.03 mol KOH is reacted then 0.03 mol HCl must also be present.
b.) HCl(aq) + NH3(aq) ) → NH4Cl(aq)
If 2 moles of NH3 are reacted then 2 moles of HCl must also be present since 1 HCl reacts with 1 NH3 from the balanced reaction.
c.) 2HCl(aq) + Ca(OH)2(s) → CaCl2(aq) + 2H2O(ℓ)
We can see that 2 HCl react with 1 Ca(OH)2, hence if 0.1 mol of Ca(OH)2 is reacted then 0.2 mol HCl must also be present.
A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:
<span>
Organic Compound + Oxygen = CO2 + H2O
</span><span>To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.
</span><span>
7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C
Therefore, 0.167 mol of C was originally in the sample.</span>
Answer:
1/45 or 0.0222 g/s
Explanation:
rate of reaction = quantity of reactant used/time taken
= (10-8)/90
= 1/45 or 0.0222 g/s
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hope this helps
Explanation:
a prolong storm will occur
that's what I found
