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erica [24]
3 years ago
13

When air pressure rapidly falls, what weather change usually occurs?

Chemistry
1 answer:
Mama L [17]3 years ago
8 0

hope this helps

Explanation:

a prolong storm will occur

that's what I found

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Calculate the percentage of a solution formed by dissolving 10g of glucose in 240g of water
bonufazy [111]
X=240 g NaCl salt dissolves in solution.
Example: If we add 68 g sugar and 272 g water to 160 g solution having concentration 20 %, find final concentration of this solution.
Solution:
Mass of solution is 160 g before addition sugar and water.
100 g solution includes 20 g sugar
160 g solution includes X g sugar
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
X=32 g sugar
Mass of solute after addition=32 + 68=100 g sugar
Mass of solution after addition=272 +68 + 160=500 g
500 g solution includes 100 g sugar
100 g solution includes X g sugar
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
X= 20 % is concentration of final solution.
8 0
4 years ago
Convert 7.9 x 10^22 atoms of Ca to grams
Vika [28.1K]

Answer:

Mass = 5.24 g

Explanation:

Given data:

Number of atoms of Ca = 7.9×10²² atoms

Mass of Ca = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole contain 6.022×10²³ atoms

7.9×10²² atoms × 1 mol /6.022×10²³ atoms

1.31 ×10⁻¹ mol

0.131 mol

Mass of Ca:

Mass = number of moles × molar mass

Mass = 0.131 mol × 40 g/mol

Mass = 5.24 g

6 0
3 years ago
Can someone please help ill mark you as brainlest
dexar [7]
Its the molecules have 20 electrons so the bear fainted.
5 0
3 years ago
Read 2 more answers
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con
anyanavicka [17]

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 }  *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O}  *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

5 0
3 years ago
Match the following family of elements to its group.
docker41 [41]

Explanation:

To solve this problem, we simply use the periodic table of elements which groups elements based on their atomic numbers.

The atomic number of an element is the number of protons it contains. The protons are the positively charged particles within an atom.

  • The vertical arrangement of elements on the periodic table is the group.
  • The horizontal arrangement of elements is the period.

Now;

Noble gases  belongs to group 18

Alkali earth metals belongs to group 2

Halogens belongs to group  17

Alkali metals belongs to group 1

Transition metals belongs to group 3-12

7 0
3 years ago
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