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4 years ago

At what characteristic wavelength does a blackbody at room temperature radiate?

Chemistry

1 answer:

DochEvi [55]4 years ago

8 0

Answer:

9.73154 × 10⁻⁶ m, infrared region

Explanation:

Using Wien's displacement law which states that the temperature and the wavelength of the blackbody radiation are inversely proportional.

So,

λmax= b/T

Where,

λmax is the peak of wavelength

b is the Wien's displacement constant having value as $2.9\times 10^{-3}\ m K$

T is the Absolute Temperature in Kelvins . Room temperature = 298 K

So,

λmax= b/T = $\frac{2.9\times 10^{-3}}{298}$ = 9.73154 × 10⁻⁶ m

This wavelength corresponds to infrared region.

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4 Nitrogen monoxide reacts with oxygen like this:

olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

$\tt \dfrac{1}{2}\times 1=0.5$

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

$\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3$

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0

3 years ago

If you answer this by tomorrow i will mark you as brainlies plz try your best it is really important.!!!! Word Definition Pictur

Romashka [77]

Answer:

This is the Hierarcy of Orginzation

Many molecules make up cell

many cells make up tissues

tissues make up organs

organs make up organ system

and so on (u can look it up)

Explanation:

Bio Teacher

3 0

3 years ago

8)How many grams are in 0.02 moles of beryllium iodide, BeI2?

n200080 [17]

Answer:

0.03:---$7--$-$7$--$-$-$$-$+-$$7-$$-$7-$8$+$-$

4 0

3 years ago

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0

4 years ago

How many molecules are in 1.5 moles of carbon dioxide

Karo-lina-s [1.5K]

Answer:

<h2>9.03 × 10²³ molecules</h2>

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ molecules</h3>

Hope this helps you

3 0

3 years ago