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ella [17]
4 years ago
8

Indicate on the chart whether you would classify each model as representing an element, compound, or mixture.

Physics
2 answers:
Nesterboy [21]4 years ago
7 0
Element
Mixture
Element
Element
Compound
Compound
Mixture
Compund
Ne4ueva [31]4 years ago
4 0

Answer:

1 compound

2 mixture

3 elements

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When a researcher wants to correlate tension with depression, she develops tests that measure these two emotional states. The te
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The answer is: measuring instrument

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The researcher develops test to measure the variables she is interested in. So, they are her measuring instrument.

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the particles that make up a rock are constantly in motion however a rock does not visibly vibrate. why do you think this?
Ivahew [28]

I think this is because the particles don't know or care about each other,
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3 0
3 years ago
What is the mass of 3 m3 of a substance having density 1200 kg/m3​
adell [148]

Answer:

3600 kg

Explanation:

From the question,

Density = Mass/Volume

D = M/V.............................. Equation 1

Where D = Density of the substance, M = mass of the substance, V = Volume of the subtance.

Make M the subject of the equation

M = D×V ............................ Equation 2

Given: D = 1200 kg/m³, V = 3 m³.

Substitute these values into equation 2

M = 1200×3

M = 3600 kg.

Hence the mass of the substance is 3600 kg

4 0
3 years ago
A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

5 0
3 years ago
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