Answer:
a)
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
The acceleration of the bicycle and rider is -1.5 m/s²
Force
The magnitude of the average force needed to bring the bicycle and its rider to a stop is
LiNos what is the moler mass
1 answer:
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Answer:
Total pressure in atmosphere IS 4.36 atm
Explanation:
Given Data:
Depth of lake is 400 mtr
surface tension is 147 kilopascals
surface temperature 94 kelvin
Gravity = 1.35 m/s^2
specific gravity of methane(liquid) = 0.415
specific gravity of ethane(liquid) = 0.546
density of methane can be obtained as
Density of ethane can be obtained as
Total pressure in atmosphere can be obtained as
= 441.84 kPa
= 4.36 atm
The average force of the water droplets is the force given by the impact
per second of the droplets on the limestone floor.
- The average force exerted on the limestone floor is approximately <u>1.6013 × 10⁻² N</u>
Reasons:
The given parameters are;
Volume of a droplet = 10 ml = 1 × 10⁻⁵ m³
Height from which the water falls, <em>h </em>= 5 meters
Rate at which the water falls = 10 per minute
Required:
The average force exerted on the floor by the water droplets.
Solution:
According to Newton's Second Law of motion, we have;
Force = Rate of change of momentum
Momentum = Mass × Velocity
Mass of a droplet of water = Volume × Density
Density of water = 997 kg/m³
Mass of a droplet = 1 × 10⁻⁵ m³ × 997 kg/m³ = 0.00997 kg
The velocity just before the droplet reaches the ground, v = √(2·g·h)
Where;
g = Acceleration due to gravity ≈ 9.81 m/s²
Which gives;
v = √(2 × 9.81 m/s² × 5 m) ≈ 9.905 m/s
The rate of change in momentum per minute = 1
Therefore;
ΔMomentum = Mass × ΔVelocity
Considering the 10 drops per minute, we have;
ΔMomentum = 10 × 0.0097 kg × 9.905 m/s = 0.960785 kg·m/s
ΔTime = 1 minute = 60 seconds
Therefore;
- The average force exerted on the limestone floor by the droplets of water is
≈ <u>1.6013 × 10⁻² N</u>
Learn more about Newton's Second Law of motion and force exerted water here: