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2 years ago

In the center of the Milky Way galaxy is a A

Physics

2 answers:

olchik [2.2K]2 years ago

5 0

The answer is the Galactic Center I think

LekaFEV [45]2 years ago

4 0

Answer:

a super massive blackhole

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if somebody swim to the right for 30 meters then swims to left for 15 meters and then swims back to the right for 50 meters what

zubka84 [21]

50m

Explanation:

Displacement is the length of path traveled which is measured from start to the finishing of the path.

Analysis of the journey;

Starts from:

0 30m from right

15m to left

50m to right

The displacement is 50m from the starting point.

Distance is total path traveled and for this problem it is 30+ 15 + 50 = 95m

learn more:

displacement brainly.com/question/5461768

#learnwithBrainly

8 0

2 years ago

How far from the castle wall does the launched rock hit the ground?

lina2011 [118]

King Arthur's knights use a catapult to launch a rock from their vantage point on top of the castle wall, 14 m above the moat. The rock is launched at a speed of 27 m/s and an angle of 32degrees above the horizontal.

4 0

3 years ago

Read 2 more answers

How does gravity keep the moon in orbit around earth

lidiya [134]

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

3 0

2 years ago

A man exerts a constant force to pull a 51-kg box across a floor at constant speed. He exerts this force by attaching a rope to

Vitek1552 [10]

Answer:

W=561.41 J

Explanation:

Given that

m = 51 kg

μk = 0.12

θ = 36.9∘

Lets F is the force applied by man

Given that block is moving at constant speed it mans that acceleration is zero.

Horizontal force = F cos θ

Vertical force = F sinθ

Friction force Fr= μk N

N + F sinθ = m g

N = m g - F sinθ

Fr = μk (m g - F sinθ)

For equilibrium

F cos θ = μk (m g - F sinθ)

F ( cos θ +μk sinθ) = μk (m g

Now by putting the values

F ( cos 36.9∘ + 0.12 x sin36.9∘)=0.12 x 51 x 10

F= 70.2 N

We know that Work

W= F cos θ .d

W= 70.2 x cos 36.9∘ x 10

W=561.41 J

3 0

3 years ago

An infinite line of charge with charge density λ1 = 0.6 μC/cm is aligned with the y-axis.

Ganezh [65]

Answer:

1440 × 10⁴ N/C

Explanation:

Data provided in the question:

Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m

a = 7.5 cm = 0.075 m

Now,

Electric field due to a line charge at a distance 'a' is given as:

Ex(P) = $\frac{\lambda}{2\pi\epsilon_0a}$

also,

we know

$\frac{1}{4\pi\epsilon_0}$ = 9 × 10⁹ Nm²/C²

Thus,

we have

Ex(P) = $\frac{2}{2}\times\frac{\lambda}{2\pi\epsilon_0a}=\frac{2\lambda}{4\pi\epsilon_0a}$

therefore,

Ex(P) = $\frac{2\times6\times10^{-5}\times9\times10^9}{0.075}$

= 1440 × 10⁴ N/C

8 0

3 years ago